-5x^2=-540

Solution for -5x^2=-540 equation:

-5x^2=-540

We move all terms to the left:

-5x^2-(-540)=0

We add all the numbers together, and all the variables

-5x^2+540=0

a = -5; b = 0; c = +540;
Δ = b2-4ac
Δ = 02-4·(-5)·540
Δ = 10800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10800}=\sqrt{3600*3}=\sqrt{3600}*\sqrt{3}=60\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{3}}{2*-5}=\frac{0-60\sqrt{3}}{-10}
=-\frac{60\sqrt{3}}{-10}
=-\frac{6\sqrt{3}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{3}}{2*-5}=\frac{0+60\sqrt{3}}{-10}
=\frac{60\sqrt{3}}{-10}
=\frac{6\sqrt{3}}{-1}
$